WebSOLUTION. Here, the focal chord of y2 =16x is tangent to circle (x−6)2+y2 = 2. ⇒ Focus of parabola as (a,0) i.e. (4,0) Now, tangents are drawn from (4,0) to (x−6)2+y2 = 2. Since, P … WebFocal chord to y 2=16 x is tangent to x 62+ y 2=2 then the possible values of the slopes of this chords,areA. 1,1B. 2,2C. 2, 1/2D. 2, 1/2 Question Focal chord to y 2 = 16 x i s t a n g e n t t o ( x − 6 ) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are
Focal chord to y 2=16 x is tangent to x 62+ y 2=2 then the …
WebJan 23, 2024 · Here, the focal chord to y2 =16x is tangent to circle (x−6)2+y2 =2 ⇒ focus of the parabola is (4,0) Now, tangent are drawn from (4,0) to (x−6)2+y2=2 Since, P A is tangent to circle and equals to 2 , (from diagram using distance formula) tanθ= slope of tangent =AP AC = 2 2 =1 or tanθ =BP BC =−1 ∴ Slope of focal chord as tangent to … WebDec 23, 2024 · The tangent to the Parabola that is parallel to y=4x+1 is: y = 4x+5/16 Which meets the Parabola at the coordinate: (5/64,5/8) We have a parabola given by: y^2=5x graph{y^2=5x [-5, 5, -5, 5]} The gradient of the tangent to a curve at any particular point is given by the derivative of the curve at that point. So if we differentiate the parabola … cistanche for diabetes
The focal chord of \( y^{2}=16 x \) is tangent to \( \mathrm{P ...
WebMar 14, 2024 · It is given that the focal chord is tangent to the circle which means that the distance of the focal chord from the center of the circle is equal to the radius of the circle. Therefore, we get m x − y − 4 m 1 + m 2 = 2 Now we will put the value of x = 6 and y = 0 in the above equation, we get ⇒ 6 m − 0 − 4 m 1 + m 2 = 2 WebA chord which passes through the focus of a parabola is called a focal chord. A given chord will be a focal chord if the point \((0,a)\) lies on it. Substituting these coordinates into the equation of the chord above we have ... and substituting \(x=2ap\). In either case, the gradient of the tangent to \(x^2=4ay\) at the point \(P(2ap,ap^2 ... WebT is a point on the tangent to a parabola y 2 = 4ax at its point P. TL and TN are the perpendiculars on the focal radius SP and the directrix of the parabola respectively. Then. A. SL = 2 (TN) B. 3 (SL) = 2 (TN) C. ... Let PSQ be the focal chord of … cistanche herba